X^2-10x+20=180

Solution for X^2-10x+20=180 equation:

X^2-10X+20=180

We move all terms to the left:

X^2-10X+20-(180)=0

We add all the numbers together, and all the variables

X^2-10X-160=0

a = 1; b = -10; c = -160;
Δ = b2-4ac
Δ = -102-4·1·(-160)
Δ = 740
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{740}=\sqrt{4*185}=\sqrt{4}*\sqrt{185}=2\sqrt{185}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{185}}{2*1}=\frac{10-2\sqrt{185}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{185}}{2*1}=\frac{10+2\sqrt{185}}{2}
$